Quick Math question solution
 

ok this is a simple math problem problem that im having trouble with plz help.

ok

3/4 y - 1/4 y= 5


ive tried 2 different solutions and still cant find the answer. cuss:

you lost me... what kind of math is this? Just algebra solving for y? What are the underscores for? And the numbers on the top and bottom?
EDIT: nvm you editted it

y=10

3/4y - 1/4y = 1/2y
then
1/2y=5
so 5/.5 = 10

is 1/4 and 3/4 a fraction, or is it 4 divided by 3 etcs

aight, thanks man.

These are some of the basic problems that we'll be tested on in the actual GED test. Simple enuff eh? I suggest you all stay in school

that shouldn't really matter. Fraction bars mean division.

it equals 2.5

3\4y - 1\4y=5
subtract them
1\2y=5
divide 1\2y by 1\2 and do the same to 5
thus
y=2.5

[quote="@/\/G3L":583a4]it equals 2.5

3\4y - 1\4y=5
subtract them
1\2y=5
divide 1\2y by 1\2 and do the same to 5
thus
y=2.5[/quote:583a4]

oOo:


y=10

[quote="@/\/G3L":9c7b9]it equals 2.5

3\4y - 1\4y=5
subtract them
1\2y=5
divide 1\2y by 1\2 and do the same to 5
thus
y=2.5[/quote:9c7b9]
close, but 5 divided by 1/2 = 10 not 2.5. You are mulitpying when you should be dividing

keywords: Order of Operations

Please Excuse My Dear Aunt Sally (Paranthases, exponents, mult./division, addition/subtraction)

Please Shut The Fuck Up Right Now (Please Shut The Fuck Up Right Now).

happy: biggrin:

i wish they taught that to us in 5th grade. the_finger:

I Agree the answer is 10. Both sides of the equation bust be multiplied by 2 to isolate the y. Multiplying the left side of the equation leaves you with y, and multiplying the right side of the equation leaves you with 10. Thus y=10.

just make all the denominators the same and its easy oOo:

( 3y - 1y = 20)
(2y = 20)
(y=10)

wtf didnt see that other y. oOo: yep its 10.

k, lets see if you guys could answer some good ol' Algebra 2 questions.

[5 2 -3] [a] [-5]
[-4 0 -4] [b] = [20]
[-3 -5 -5] [c] [53]

Solve for A, B, and C.

Note: This is only one problem, so each line doesn't seperate a different problem. You are trying to figure out how the first column of 3 numbers multiplied by the column ABC will equal the last column of 3 numbers.

[quote="[DAS REICH] Blitz":69893]k, lets see if you guys could answer some good ol' Algebra 2 questions.

[5 2 -3] [a] [-5]
[-4 0 -4] [b] = [20]
[-3 -5 -5] [c] [53]

Solve for A, B, and C.

Note: This is only one problem, so each line doesn't seperate a different problem. You are trying to figure out how the first column of 3 numbers multiplied by the column ABC will equal the last column of 3 numbers.[/quote:69893]

Here's one for you....

Blitz + check PM's = ?

stay in school kids

[quote="9mm BeRetTa":d3d1a]just make all the denominators the same and its easy oOo:

( 3y - 1y = 20)
(2y = 20)
(y=10)[/quote:d3d1a]

i did the same thing

[code:2f1eb]

X X Y Z ?

X W Y W 85

Z Y X Z 87

W X Y Z 82

87 86 93 79
[/code:2f1eb]

Solve the first line. There are two methods one can use to arrive at the
correct answer and unfortunately, the easy way isn't, by reason of four
variables. Let's see who knows his Algebra...

Minor edit:

1) All lines are composed exclusively of additions. (W+X+Y+Z=82)
2) I will post the complete solution in a day.

^ i dont

[quote="[DAS REICH] Blitz":cda00]
[5 2 -3] [a] [-5]
[-4 0 -4] [b] = [20]
[-3 -5 -5] [c] [53]

Solve for A, B, and C.
[/quote:cda00]

I've understood the above to mean the equivalent of

5a + 2b - 3c = -5
-4a - 4c = 20
-3a - 5b - 5c = 53

after manipulation of the matrices, in which case the problem solves for
A = -1
B = -6
C = -4

I can post the entire solution if you want.

Here's an Algebra problem I've created:

[code:53b64]

X X Y 40

Z Y Z 50

X Y Z ?

35 50 50
[/code:53b64]

I want you to solve it WITHOUT resorting to an individual variable solution,
that is to say I don't want you solving X, then Y and Z: there's an alternate
way of finding the value of the line. Simple numerical answers will not count:
I want the details of your solution.

[quote="Mr.Buttocks":e2813][quote="[DAS REICH] Blitz":e2813]k, lets see if you guys could answer some good ol' Algebra 2 questions.

[5 2 -3] [a] [-5]
[-4 0 -4] [b] = [20]
[-3 -5 -5] [c] [53]

Solve for A, B, and C.

Note: This is only one problem, so each line doesn't seperate a different problem. You are trying to figure out how the first column of 3 numbers multiplied by the column ABC will equal the last column of 3 numbers.[/quote:e2813]

Here's one for you....

Blitz + check PM's = ?[/quote:e2813]fin.

[quote=SoLiDUS]I've understood the above to mean the equivalent of

5a + 2b - 3c = -5
-4a - 4c = 20
-3a - 5b - 5c = 53

after manipulation of the matrices, in which case the problem solves for
A = -1
B = -6
C = -4

I can post the entire solution if you want.[/quote:7442e]

wow, you got it right... dam i thought no one would get it.

As promised, the solutions to my problems

[code:593bc]

X X Y 40

Z Y Z 50

X Y Z ?

35 50 50
[/code:593bc]

Solution:

(X+Y+Y) + (Y+Z+Z) + (X+Z+X) - (X+X+Y) - (Y+Z+Z) = X + Y + Z

( (X+Y+Y) + (Y+Z+Z) + (X+Z+X) ) - ( (X+X+Y) - (Y+Z+Z) ) = X + Y + Z

( 50 + 50 + 35 ) - ( 40 + 50 ) = 135 - 90 = 45


[code:593bc]

X X Y Z ?

X W Y W 85

Z Y X Z 87

W X Y Z 82

87 86 93 79
[/code:593bc]

Solution:

Use line worth 79 and solve w = 79 - 3z

2x + (79 - 3z) + z = 87
2x + 79 - 2z = 87
2x - 2z = 8
2x - 8 = 2z
Solve for z = x - 4

2 (x - 4) + x + y = 87
2x -8 + x + y = 87
3x + y = 95
Solve for y = 95 - 3x

3y + x = 93
3 (95 - 3x) + x = 93
285 - 8x = 93
192 = 8x
Solve for x = 24

Since z = x - 4,
Solve z = 24 - 4 = 20

Since y = 95 - 3x,
Solve y = 95 - 3(24) = 95 - 72 = 23

Since we know X, Y and Z, we can solve the first line:
24 + 24 + 23 + 20 = 91